m^2-(1/3)m-(2/9)

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Solution for m^2-(1/3)m-(2/9) equation: 


m in (-oo:+oo)

m^2-((1/3)*m)-(2/9) = 0

m^2+(-1/3)*m-2/9 = 0

m^2-1/3*m-2/9 = 0

DELTA = (-1/3)^2-(-2/9*1*4)

DELTA = 1

DELTA > 0

m = (1^(1/2)+1/3)/(1*2) or m = (1/3-1^(1/2))/(1*2)

m = 2/3 or m = -1/3

m in { -1/3, 2/3 }

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